10x^2-100x+220=0

Solution for 10x^2-100x+220=0 equation:

10x^2-100x+220=0

a = 10; b = -100; c = +220;
Δ = b2-4ac
Δ = -1002-4·10·220
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-20\sqrt{3}}{2*10}=\frac{100-20\sqrt{3}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+20\sqrt{3}}{2*10}=\frac{100+20\sqrt{3}}{20}
$